
Not sure. I'll post one soon. Just haven't because I am still waiting for this baby to come. She has given me two false alarms and I am now over due. I get induced Wensday if she doesn't come by then.
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Misato wrote:For the sake of my boredom...I always enjoy this one.
1
11
21
1211
111221
312211
13112221
What 2 rows of numbers comes next in this series?
Misato wrote:For the sake of my boredom...I always enjoy this one.
1
11
21
1211
111221
312211
13112221
What 2 rows of numbers comes next in this series?
gejyspa wrote:I know the answer, Misato, so I won't give it.. but here's one I gave my kids.. it took them FOREVER, with lots of hints, to get it.. what numbers come next in this sequence:
3, 3, 5, 4, 4, 3, 5, 5, 4, _, _, _ ?
Peter wrote:gejyspa wrote:I know the answer, Misato, so I won't give it.. but here's one I gave my kids.. it took them FOREVER, with lots of hints, to get it.. what numbers come next in this sequence:
3, 3, 5, 4, 4, 3, 5, 5, 4, _, _, _ ?
(1) 3,3;(2) 5;(3) 4,4;(4) 3;(5) 5,5;(6) 4 I made groups of (a) number(s) here split by ";". Any group of (a) number(s) is changed three groups later, the double become solo and the solo becomes double. Group 1 (3,3) is later in group 4 (3). Group 2 (5) becomes (5,5) in group 5.
Group 7 should be the alternate for group 4 (3,3)
Group 8 should be the alternate for group 5 (5)
This would mean 3,3,5
gejyspa wrote: You would think, but no.... and in fact, I will GIVE you next three, and ask you for the three after that:
3, 3, 5, 4, 4, 3, 5, 5, 4, 3, 6, 6, _, _, _
gejyspa wrote:But essentially, you are using one cycles (of 3 groups) and using that as a basis for you solution. There are infinite solutions that just use one cycle. For example, I could have argued, with similar reasoning to yours, that it should be 6,6,3, because the pairs go up by one each time, and singletons cycle through 3,5,4,3,5,4. There isn't enough basis for you to make that claim, because your groups are too big to be meaningful...
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