Collatz conjecture

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kroner
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Postby kroner » Tue Aug 17, 2004 8:46 pm

Thomas Pickert wrote:Welcome back, Richard. :)

While you were away, I advertised Serenity to fill a bit of the hole you left.
It's German, and it's a math forum. But that's all you can expect from an amateur. I'm glad I can leave that to the pro again. ;)

Thomas, you have to put more math problems up!
I was so happy when there was math on the forum...
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Thomas Pickert
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Postby Thomas Pickert » Tue Aug 17, 2004 8:52 pm

Start with a random natural number greater than 0.

If it's even, divide by 2. If it's odd, multiply with 3 and add 1.

Do you always end with 4, 2, 1, 4, 2, 1, ...?
Appleide
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Postby Appleide » Wed Aug 18, 2004 6:18 am

no.
Cherize
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Postby Cherize » Wed Aug 18, 2004 11:26 am

3 x 3 = 9 + 1 = 10
Cherize
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Postby Cherize » Wed Aug 18, 2004 11:30 am

Thomas Pickert wrote:Start with a random natural number greater than 0.

If it's even, divide by 2. If it's odd, multiply with 3 and add 1.

Do you always end with 4, 2, 1, 4, 2, 1, ...?


But it will always be even.
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Thomas Pickert
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Postby Thomas Pickert » Wed Aug 18, 2004 12:01 pm

I forgot to add, that you reiterate the procedure endlessly, of course. ;)

@Cherize: I don't understand. 6 : 2 = 3 is odd, for example.
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kroner
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Postby kroner » Wed Aug 18, 2004 12:32 pm

the short answer is yes (i think). but i still have to come up with a proof... hmmm.
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Thomas Pickert
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Postby Thomas Pickert » Wed Aug 18, 2004 1:04 pm

I have split this off Richard's "I'm back" post now. I have also added the name of the problem described, to make it easier to understand for those who really try to find a proof, what kind of problem they're trying to tackle. ;)
The Industriallist
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Postby The Industriallist » Wed Aug 18, 2004 9:32 pm

Translation: one that hasn't been proven yet by anyone, correct?
"If I can be a good crackhead, I can be a good Christian"

-A subway preacher
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Thomas Pickert
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Postby Thomas Pickert » Wed Aug 18, 2004 9:45 pm

Yes.

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